PHP解析JSON数据
时间：2021-07-01 10:21:17
帮助过：13人阅读
- $json_string='{"id":1,"name":"rolf","country":"russia","office":["google","oracle"]} ';
- $obj=json_decode($json_string);
- //print the parsed data
- echo $obj->name; //displays rolf
- echo $obj->office[0]; //displays google
|
PHP, JSON
