0){ while($row = mysqli_fetch_array($run_query)){ $">
时间:2021-07-01 10:21:17 帮助过:5人阅读
Categories
    ";
if(mysqli_num_rows($run_query)>0){
    
        while($row = mysqli_fetch_array($run_query)){
            $cid = $row["cat_id"];
            $cat_name = $row["cat_title"];
            echo "
$cat_name 
            ";
        }
        echo "";
    }
}
?>//JS
$(document).ready(function() {
    cat();
    function cat() {
        $.ajax({
                url: 'action.php',
                type: 'POST',
                data: {
                    category: 1
                }
            })
            .done(function(data) {
                //console.log(data);
                $("#get_category").html(data);
            });
    }
})php是小白,有没有办法前后端分离,把echo的HTML代码返回json的格式给前端处理?