时间:2021-07-01 10:21:17 帮助过:59人阅读
这里给定一个搜索路径,需要在此目录中找出所有符合匹配模式的文件
import glob, os
def all_files(pattern, search_path, pathsep = os.pathsep):
for path in search_path.split(pathsep):
for match in glob.glob(os.path.join(path, pattern)):
yield match
print(type(all_files('*.s', 'd:\\pm\\pm')))
print(all_files('*.s', 'd:\\pm\\pm').__next__())
for match in all_files('*.s', 'd:\\pm\\pm'):
print(match)
希望本文所述对大家的Python3程序设计有所帮助。