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Navicat Premium mysql

时间:2021-07-01 10:21:17 帮助过:2人阅读

create table user3(id int(11),name varchar(32),age int (3),sex char(1)); #添加语句 insert into user3(id ,name,age,sex)values(1,‘张三‘,99,‘男‘); insert into user3 values(4,‘王五‘,21,‘男‘); #删除 delete from user3;#user3中所有数据全删 delete from user3 where name=‘张三‘; delete from user3 where name=‘张三‘ and age=99;#and 出现在条件与条件之间 delete from user3 where name=‘张三‘ & age=99;#???为何没效果 &最好不用,Java中转义字符 #修改 update user3 set sex=‘女‘ where name=‘李四‘ and age=22; update user3 set sex=‘女‘,age=2 where name=‘李四‘ and age=22;#同时改多个 #查询 select name,id,age,sex from user3;#查询所有 select * from user3;#查询所有 顺序 select name from user3;#查询所有姓名 select id,name,age,sex from user3 where name=‘李四‘ and age=2; select id,name,age,sex from user3 where name=‘李四‘ or age=2; select * from user3 order by id asc;#按id 升序排列 select * from user3 order by id desc;#按id 降序排列

 

Navicat Premium mysql

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