时间:2021-07-01 10:21:17 帮助过:5人阅读
$row = 1;
$handle = fopen("test.csv","r");
while ($data = fgetcsv($handle, 1000, ",")) {
$num = count($data);
echo " $num fields in line $row:
\n";
$row++;
for ($c=0; $c < $num; $c++) {
echo $data[$c] . "
\n";
}
}
fclose($handle);
#我用上面的代码获取
#date
#2011-4-21
#的数据能正常获取
#你的问题怎么解决的?